$=10+3x-x^2$
$\left(140-3x\right)^2$
$n2+9n-10$
$\frac{dy}{dx}=\left(1+y\right)\left(8+x\right)$
$8x^2-2x-3$
$b^2=3b+10$
$\frac{dy}{dx}=\frac{1}{\left(x+8\right)y^2}$
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