$\left(\frac{4}{5}x^2-\frac{2}{3}x-\frac{1}{2}\right)\left(\frac{6}{5}x^2-3x\right)$
$\left(x-5\right).\:\left(x+2\right).\:\left(x-3\right)^2$
$x^2+20x-10$
$1+5\:-2-3-3$
$-9+7+\left(-3\right)+19+13$
$\frac{36^4-121^6}{6a^2+11p^6}$
$\frac{dy}{dx}=4-y$
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