$\frac{-2x}{x}$
$\frac{2}{3}e^{3x}x+\frac{1}{3}e^{3x}-\frac{2}{9}e^{3x}$
$\left(a\:+\:3\right)\left(a\:+\:1\right)\:-\:4\left(a\:+\:1\right)$
$\int\frac{3^x}{3}dx$
$4x^2+20x+9$
$-27\:-\:\left(4+4\right)\left(3\right)$
$-\left(4x-6\right)^2$
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