$\int\frac{x+4}{\left(x^2-3x+2\right)}dx$
$\frac{dy}{dx}=-8x$
$\int\frac{3}{\left(1-x^2\right)}dx$
$\lim_{x\to7}\left(v\right)$
$\left(8c^3-5b^2\right)\left(8c^3+7b^2\right)$
$\frac{5x^2+41x+43}{x+7}$
$\frac{d^2}{dx^2}\left(\frac{1}{x-1}\right)$
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