$\left(3x^3+y\right)\left(3x^3-7\right)$
$64x^280x+25$
$6z-3+4z$
$1-8d+16d^2$
$\frac{dy}{dx}\left(3xy^2=2+3x\right)$
$\left(-15\right)\left(_{-5\left(2\right)}\right)$
$\left(12x^{10}+9\right)^2$
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