$0.004+389.4+39.456+0.5+16$
$x=\left(x+y\right)^2+\ln\left(x+1\right)$
$1+\left(-35\right)+\left(-33\right)$
$\int\:\left(6x^3+2\sqrt[3]{x^4}+1\right)dx$
$\int\frac{x^3+x^2}{x+2}dx$
$1+\frac{-2}{x+3}+\frac{2}{x-3}$
$\frac{-x^{5}yz^{-2}-2xy^{2}z^{4}+1}{2yz^{-2}}$
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