$8z-3xy-12z$
$-3x+2y=6$
$\lim_{x\to0}\left(\frac{1}{x^2-4x}-\frac{3}{x-4}\right)$
$\frac{dy}{dx}+\frac{3y}{x}+2=3x,\:\:y\left(1\right)=1$
$12.02\cdot27$
$4x^2-4x-39=0$
$5f-8+6f-6$
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