$-9\left(16+25\right)$
$\left(\frac{4}{3}m\:+5y\right)^2$
$\left(-5x^{2}+7x+6\right)=\left(-x+2\right)$
$\int4tan^4x\:dx$
$\frac{1}{y}\frac{dy}{dx}=\frac{1}{1+x}$
$8m-7m^5+3m^3$
$-\left(4-2+9-8-3+1\right)+\left(-2-4+3\right)$
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