$4^2+8-3$
$\int\frac{1}{x\sqrt{25-x}}dx$
$-6k+6-k_{-8}$
$\lim_{x\to\infty}\left(\frac{\sqrt{x+2}-3}{x^2-49}\right)$
$\left(1-3x\right)^3$
$\left(0.99\right)^2$
$\frac{1}{\cos\left(x\right)}+tan\left(x\right)=\frac{\cos\left(x\right)}{1+\sin\left(x\right)}$
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