$\lim_{x\to0}\left(\frac{2x^3-4x+3}{5x^3+3}\right)$
$\lim_{x\to4}\left(\frac{x^{2}-16}{x^{2}-6x+8}\right)$
$5x^2-3x-6$
$y^2+26y+169$
$-9m^2-2m^2$
$\frac{x^3y^5z^{-2}}{x^4y^3z^{-3}}$
$z^4\cdot z^6$
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