$\left(3+4x-4x^2\right)^{\frac{3}{2}}$
$2x^3-14x^2-10x$
$-902+-423$
$1-\left(\sin\left(x\right)\right)^2=\frac{1-\cos\left(x\right)}{2}$
$3\sqrt{8}\cdot2\sqrt{50}$
$\frac{9}{25}x^2+\frac{6}{5}xy+y^2$
$-4\:-\:\left(4\:-3\:+\:4\right)\:-\:\left(-9\:-18\:-3\right)$
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