$\left(3x+8y\right)\left(2x+4y\right)$

$10h^2-490$

$\int\:\frac{12x+13}{\left(3x+2\right)\left(2x+3\right)}dx$

$\left(4x-\frac{9}{2}y+7.5\right)\left(4x-\frac{9}{2}y+7.5\right)$

$10x^2+20x+1$

$\frac{2}{c^2-1}-\frac{1}{c-1}=\frac{1}{2}$

$-12+3-\left(8-12\right).\left(-3+6\right)-\left(-3+6\right)-\left(-3-2\right).\left(-2\right)$