$\frac{x^3}{8}+\frac{-9x^2}{4}+\frac{27x}{2}-27$
$\left(x+2\right)\left(x+3\right)\ge y$
$123,789+71+0,6+1,23$
$5-x^2>8$
$3x+4y=5x-4y$
$\left(123^2\right)\frac{2}{1}2\left(213\right)$
$3a\left(5a^2+8a+2\right)$
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