$\frac{dy}{dt}=y^2-6y-16$

$0,2\cdot0,2$

$\left(3z^3+2y^2\right)^2$

$\int5\sin^3\left(5x\right)\cos^3\left(5x\right)dx$

$2x\left(x^2+y^2\right)dy+y\left(y^2+2x^2\right)dx=0$

$\left(2x+y\right)\left(2x-y\right)=4x\left(x-1\right)$

$\frac{dy}{dx}=-\frac{3x^2+6xy}{3x^2+2y}$