$\left(5b^2c-4\right)^2$
$\left(a-3\right)-\left(3-a\right)+\left(a-3\right)^{3}$
$\frac{a^{-3}}{a^{-5}}\frac{b^4}{b^5}$
$\frac{8x^5-12x^3-16x^2}{4x^2}$
$\frac{x^2+6x-3}{x+1}$
$2\sqrt{x}\left(3x^3-4\sqrt[3]{x}\right)$
$4^7\cdot4^{-5}$
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