$\int\left(\frac{5}{x^2+4x+8}\right)dx$
$\lim_{x\to125}\left(\frac{x^{\frac{5}{3}}-5x-2500}{x^{\frac{1}{3}}-5}\right)$
$3x^2\le\left(x+2\right)^2-2x$
$\frac{4x^2+3x-2}{x-5}$
$\sqrt[4]{81\cdot0.0081\cdot0.0001}$
$\lim_{x\to3}\:\frac{27-x^3}{3-x}$
$( \frac { 1 } { 2 } x - 2 ) ^ { 2 }$
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