$1-\frac{\cos^2a}{1+\text{sina}}=\text{sina}$
$\frac{8xy-12xy+16xy}{\frac{4}{3}xy}$
$\frac{dy}{dx}=\left(4x-9\right)^2$
$3ydx+4xdy=0$
$\sqrt{11a^3b}$
$\frac{a^6b^2}{a^2b^2}$
$\int\cos^4dx$
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