$\left(\frac{a}{3}-\frac{b}{2}\right)^2$
$a^3b^3+8$
$\left(-9\right)\cdot\left(-5\right)\cdot\left(-6\right)\cdot\left(-3\right)$
$4\left(x+2\right)-20\left(x-6\right)$
$cos\left(2a+2b\right)-cos\left(2a\right)$
$1-7+3-\left(-4\right)$
$6z^2-5z-6$
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