$7^8\cdot2^8$
$\left(x^2+x+1\right)^2$
$\left(3\right)\left(-2\right)\left(-5\right)+4$
$x^2-2x+3=0$
$f\left(x\right)=xe^{-1}$
$-6+7m+8$
$-42x+21x-28x$
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