$-8+1+-9$

$\left(2+6-10\right)-3+\left(4-9\right)-8+1$

$\frac{\tan\left(x\right)}{\cos\left(x\right)}+\frac{1}{1+\sin\left(x\right)}=\frac{4}{3}$

$-143+132+-195$

$3x^2-5x+6\cdot4x-2$

$\frac{\sin\:^2\left(x\right)+5\sin\:\left(x\right)-6}{\sin\:\left(x\right)-1}$

$\left(\frac{4}{3}w^4t^5\right)^3$