$12x^2+x+1=0$
$\frac{1}{2}\left(sin\left(a+b\right)-sin\left(a-b\right)\right)$
$12x-20$
$\left(ax+b\right)^3$
$\frac{2x-1}{3}\:\ge\:-6x+10$
$\left|-2\right|+\left|8.5\right|$
$\frac{48\cdot3}{3}$
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