$\frac{d}{dx}\left(x^3\tanh\left(y\right)=y-16\right)$
$\frac{1}{2}\left(\arcsec\left(3\right)-\arcsec\left(\sqrt{3}\right)-\frac{2}{9}\right)$
$3\cdot\left(6x-4\right)+8=11x+10$
$\lim\:_{x\to\:0}\left(\frac{e^x-\left(1+x\right)}{x^3}\right)$
$\left(1-7\right)^2-\left(7-5\right)^3+\left(3-5\right)^5$
$\left(a^4-2\right)^3$
$\frac{16abc}{8abc}$
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