$\frac{x^2+3}{x^2-9}$
$\left(\frac{3}{5}\right)^2.8$
$\int\frac{\csc^2\left(2x\right)}{4-\cot\left(2x\right)}dx$
$1-15-20$
$\:\:\left(-1\right)\left(2\right)\left(-3\right)\left(1\right)\left(1\right)\left(-3\right)$
$\frac{4}{x-4}=\frac{3x}{x+3}$
$\left(a-2b+2c\right)^2$
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