$9a^2-4b^6$
$36\times40\times10$
$\left(\:x\:-\:5\:\right)\:.\:\left(\:x\:+\:3\:\right)$
$\int\frac{x+5}{x^3+x^2-6x}dx$
$\int\frac{1}{x^2\sqrt{x^2+e}}dx$
$-x^2-3x+40<0$
$\sqrt{\log_{10}\left(x\right)}=\log_{10}\left(x\right)$
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