$\left(x^2+x-2x-2\right)$
$-25\:x\:12\:x\:-4$
$\lim_{x\to0}\left(1+\frac{1}{x}\right)^{4x}$
$x^2-4x-1=0$
$\frac{1.253}{12}$
$-3+8\cdot\left(-2\right)+19-9\left(-2\right)$
$9x-3+2x-4x+11$
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