$\frac{d}{dx}\left(x^2y+y^4=4-2x\right)$

$\int_{\frac{2}{\sqrt{3}}}^2\left(t\arcsec\left(t\right)\right)dt$

$\tan^2x-81=0$

$\left(6e-6r\right)\left(6e+6r\right)$

$2x^2-2x-8\:=\:-4$

$\int\left(\frac{\left(x+5\right)}{\sqrt{x^2+10x}}\right)dx$

$\left(2-9\right)+\left|5-\left(8+2\right)\right|$