$\left(x^2-4x+3\right)\:\left(x-1\right)$
$-5r-11+9r=4r+21$
$\frac{1}{x+1}+\frac{x}{x-2}$
$5+13.53$
$x=2x$
$\left(x+2b\right)\left(x+4b\right)$
$4-6-7\cdot1$
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