$\frac{\left(x^2-x\right)}{\left(3x-2\right)}y'=\frac{1}{2y}$
$3tan^2u-\sqrt{3}tanu=0$
$\cos\left(2x\right)=1\:-\:\sin\left(x\right)$
$\int\frac{x}{\left(x^2+1\right)\left(x-2\right)^2}dx$
$\frac{w^9-343}{w^3+8}$
$-55+4$
$\left(-4\right)\:-\:4prompt\:1\:answer$
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