$73+10^3$
$\left(\frac{x}{1}\right)^3$
$\int_0^1\left(4xy\right)dx$
$1+\left(-50\right)+\left(-35\right)$
$9+x=11$
$\:6\left(7x+2\right)+7$
$\frac{1}{secx+1}-\frac{1}{secx-1}=-2cot^2x$
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