$\int\frac{5x^2+x+3}{x\left(x^2+4\right)}dx$
$x^2x+9$
$x\left(\frac{dy}{dx}\right)+3y=cos\left(x\right)$
$-1\:+\:5\:+\:18\:+\:13$
$y^8-5y^4+4$
$\frac{2x}{x-3}-\frac{2x}{x+3}$
$4x^2-12xy+16y^2$
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