$\left(-4\right).\left(10-12\right)+\left(15-4-1\right):\left(-5\right)$
$x^2-4x+3>=0$
$\lim_{x\to0}\left(\frac{6\sin\left(4t^3\right)}{-5t}\right)$
$x^2+12x+10=38$
$\int\:\:\left(ctg\:x\right)dx$
$\sqrt[5]{9^{15}}$
$2x^2=12$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!