$\int\left(10-20x\right)\left(e^{-5x^2+5x-1}\right)dx$
$\frac{600}{38.4846}$
$\left(\tan x+\cot x\right)\sec^2x-\cot x$
$\left(ab-2b\right)\left(ab+2b\right)$
$3x^2+3x-4=0$
$14-41-\left(-20\right)$
$\left(x^{-2x}\right)\left(-x^x\right)$
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