$\lim_{x\to\infty}\left(\frac{3^x}{xe^x}\right)$
$x+2x^2+x^3$
$\frac{x^2+2x+6}{x-3}$
$\left(y^3+y\right)\frac{dy}{dx}$
$\sqrt{-3.\:\left(-8\right)+\left(-5\right)^2}$
$\tan^2x+2\sec^2x$
$\:y^{-4}z^5\:$
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