$\left(\frac{3}{4}t+\frac{1}{5}q\right)\left(\frac{3}{4}t-\frac{1}{5}q\right)$
$x^2+20x+9$
$\int_1^{\infty}sin\left(2x\right)dx$
$\left(-7m-6x\right)^2$
$x^2+1>6$
$-t^3\:+\:6t^2\:+\:15t\:$
$\frac{dy}{dx}\left(x+1\right)=-y+10$
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