$\left(x+y+1\right)=\frac{dy}{dx}$

$3x\left(1-x\right)$

$\int\left(\frac{3}{\left(1+4x^2\right)}\right)dx$

$\int\:\frac{1}{\left(x+3\right)^2+16}dx$

$\left(s+1-y\right)\left(s+1+y\right)$

$\frac{1}{\left(1-cosx\right)\left(1+cosx\right)}$

$\frac{1+\frac{1}{\cos\left(x\right)}}{\frac{\sin\left(x\right)}{\cos\left(x\right)}+\sin\left(x\right)}$