$\frac{d}{dx}x^2-y^2=xy$
$\left(x^2+2xy\right)^2$
$\left(by+zy^2\right)$
$\int_0^{x^2}\:\left(\frac{xe^{3y}}{9-y}\right)dx$
$3x^4-6x^3-4x^2-10\cdot x^3+2^2$
$\frac{4x^3-10x^2+6x+7}{2x}$
$\int\frac{x^3+1}{x^2\left(x-1\right)^2.\left(x^2+1\right)^2}dx$
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