$\lim_{x\to-\infty}\left(\left(\frac{\sqrt{9x^6-x}}{x^3+4}\right)\right)$

$5x-18<12-3x$

$16\cdot483x+2$

$\left(8x^6-27y^9\right)$

$\lim_{x\to\infty}\left(\frac{\left(e^x\right)^2+x}{e^x}\right)$

$y=2^{x+2}+2$

$\sqrt{6\cdot\left(-3\right)+3+\left(-4\right)\cdot\left(-6\right)-\sqrt{2^4+9}+2^1}$