$5x^2-27x-10$
$0\cdot\left(10\right)\cdot\left(-19\right)\cdot\left(-38\right)$
$\left(p^2q^2\right)^2$
$4243x+y;\:x=7;\:y=10$
$\lim_{x\to5}\left(\frac{3x^2+4x}{x^2-25}\right)$
$\frac{2x^2-11x+8}{x+4}$
$x+6=-\frac{1}{2}x$
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