$10x+8=8x+16$
$\frac{8x^5y}{y^4}\cdot\frac{5y}{4x^2}$
$x^2-4xy+4y^2-1$
$3x-4x^2+8x-9x+5x^2+6x-11x^2$
$x:\left(-5\right)-2\le-3$
$\left(-3\right)\:+\:\left(-8\right)\:+\:\left(-4\right)\:-\:2\:x\:\left(-2\right)$
$2a^2+5a+2=0$
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