$2r^2+6r+7+3r^2+5r+8$
$3\left(2x-8\right)=6$
$\frac{d}{dx}\sqrt{x+3}-5$
$y'\:=\:-4y$
$y-y-5y$
$\left(x+3\right)\left(x-7\right)+2\left(x^2+2x+10\right)$
$3x^2-7x-6=0$
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