$3h\:-\:14g\:-\:5h\:+\:4g$

$\frac{1}{9}-\frac{49}{16}b\left(12\right)$

$\lim_{x\to-\infty}\left(1+\frac{4}{x^5}\right)^x$

$130.82-0.180\left(48.835\right)$

$m^3+m^2+m^2$

$\lim_{x\to3}\left(\frac{x^2-x+12}{x+3}\right)$

$\left(x^4-x^{-4}\right)^2-\left(x^4+x^{-4}\right)^2$