$\frac{x^2+3x}{x}$
$16x\:=\:80$
$\left(\frac{1}{1+\frac{1}{1+x}}\right)$
$6x^2+36x+1$
$\left(2x+\frac{1}{5}\right)\left(2x-\frac{1}{5}\right)$
$\left(-3^5\right)^8$
$\left(y^2\:\cdot\:-3\right)\cdot\:2$
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