$\int x^2e^xdf$
$35+\int_0^3r\left(x\right)dx$
$8\left(\frac{-3}{2}\right)^2$
$y'\:+y=e^{-3x}$
$\frac{74-6d}{d+6}$
$\sqrt[3]{64a^5b^6}$
$x''+3x'+6x=0$
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