$\left(-b-4\right)^2$
$\frac{x}{5x+5}=\frac{1}{x+2}+\frac{1}{x^2+3x+2}$
$25a^2b^6+a^2-10a^2b^3$
$4\cdot4\cdot4\cdot4^2$
$\frac{4x^3-3x^2+2}{3x^2+2}$
$\lim\:_{x\to\:-\infty\:}\frac{x}{\sqrt{x^2-4}}$
$\left(+24\right)-\left(-12\right)$
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