$\left(3x^2y+3y\right)dy-3xdx=0$
$\left(-10+5-9\right)-4-\left(-7+6\right)+2$
$2^2+2^2$
$x2\:+\:10\:x\:+\:10\:=\:0$
$3p^6q+14p^3$
$\frac{5x^4-8x^2+10}{x^2-15}$
$\frac{3x^{3}+2x^{2}+x+3}{x+2}$
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