$\left(x+10\right)^3$
$\sqrt[5]{25^{4x+1}}=\sqrt[4]{125^{2x+2}}$
$\lim_{x\to\infty}\left(\frac{14w^2+7w+3}{\sqrt{49w^4+2w^3}}\right)$
$343=x^3$
$3x+8=5x-2$
$3sen^2x\:+5cosx\:=0$
$-1-3^2$
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