$\left(8xy^3\right)^2$

$4r^2+112r-92=0$

$\sqrt{3xy}$

$\left(\frac{1}{3}+\frac{3}{2}a\right)\left(\frac{1}{3}-\frac{3}{2}a\right)$

$\lim_{x\to0}\left(\frac{\cos^2\left(4x-1\right)}{6x^2-x^3}\right)$

$7\cdot0.8$

$\left(x-0.25\right)\left(x-0.46\right)\left(x-0.60\right)$