$\int_{x-1}^{\sqrt{x}}3x+2\:dy$
$\left(\frac{2}{3}x-3\right)^2$
$x\cdot y'\:+2\cdot y=\:x^4$
$\frac{dy}{dx}=\sin\left(x\right)\cos\left(y\right)+\cos\left(y\right)\sin\left(x\right)$
$x^3-6x^2-x+6$
$-16x^2y+48y$
$3y+2z-4z$
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