$16^2+4^3\cdot2$

$x^3\frac{dy}{dx}=y^2\left(x-4\right)$

$\left(4x^2y^3\right)^4$

$\left[\left(x\right)\right]^{2-7x-30}$

$8\cdot\left(-2\right)-\left(-4\right)^2$

$\left(x-1+3i\right)\left(x-1-3i\right)\left(x+4\right)$

$\frac{1}{\left(n^3+1\right)^{\left(\frac{3}{4}\right)}}$