$-17-8+4$
$\left(4xmn+2xm^2\right)^3$
$\left(54+3b^2\right)^3$
$\frac{1}{2}\cdot7\left(6+18\right)$
$\left(41+20x\right)+\left(x^2-14x+49\right)$
$ex\:dydx=\:2x$
$4-\sin\left(x\right)=\frac{1}{\sin\left(x\right)}$
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